x^2/(0.1-x)=7*(10^-4)

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Solution for x^2/(0.1-x)=7*(10^-4) equation: 



x^2/(0.1-x)=7(10^-4)

We move all terms to the left:

x^2/(0.1-x)-(7(10^-4))=0



Domain of the equation: (0.1-x)!=0

We move all terms containing x to the left, all other terms to the right

-x!=-0.1

x!=-0.1/-1

x!=0.1/1

x∈R



We add all the numbers together, and all the variables

x^2/(-1x+0.1)-(7(10^-4))=0

We add all the numbers together, and all the variables

x^2/(-1x+0.1)-0.0007=0

We multiply all the terms by the denominator


x^2-(0.0007)*(-1x+0.1)=0

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